1. The position of the double or triple bonds must always have the lowest numbering scheme and is put in front of a parent chain. They take priority over the side chains.
CH3
|
CH2
|
CH2 = CH2 - CH2 - CH3
1 2 3 4
3 ethyl 1 butene
CH3
|
CH3 - C - CH2 - CH = CH
|
CH3
5 4 3 2 1
4, 4 diethyl 1 pentyne
2. Double bonds end in '-ene' and are known as Alkenes. In diagrams, they are represented by a double line.
3. Triple bonds end in '-yne' and are known as Alkynes.In diagrams, they are represented by a triple line.
Check out this PDF for more practice problems:
http://www.mouatonline.com/Teachers/BHutchinson/Chemistry/Chem11/Unit%207/PS%207.2%20-%20Alkenes%20etc%28ans%29.pdf
Try these videos out too and learn more about Alkenes & Alkynes!
http://www.youtube.com/watch?v=KWv5PaoHwPA
http://www.youtube.com/watch?v=TBQjbGcUcUw&feature=related
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