Hello again!
We did a Molar Volume Lab before the Winter Break and it contained a sink full of water, a graduated cyliner, and a lighter with a substance called Butane which is known for its combustive traits. But in this lab we measured how much Butane is consumed underwater on top of a graduated cylinder. This sets us up with our estimated "STP" or Standard Temperature and Pressure, which is 22.4. None of our classmates were near to the number but one of the groups recorded a 24.2, which was SATP.
Saturday, December 25, 2010
Monday, December 20, 2010
Multi-Step Conversions
Sometimes, there will be cases where you will be given information that you would have to use in order to make numerous conversions. Here are some examples:
EXAMPLE:
12.5 grams of Hydrogen (H2) are placed in a balloon at STP (Standard Temperature and Pressure = 0ยบ C & 101.3 kPa). Determine it's volume.
1. First, use molar mass as your conversion factor and cancel accordingly.
-> 12.5g of H2 x 1 mol
2.0g*
*The mass in grams is 2.0 because there are hydrogen is diatomic.
2. Next, use molar volume as your conversion factor and cancel accordingly.
-> 12.5g of H2 x 1 mol x 22.4 L
2.0g 1 mol
3. Alter your answer to have the appropriate number of significant digits.
-> There are 1.4 x 10² Liters in 12.5 grams of Hydrogen.
There will be other instances where they ask you for more conversions such as grams to atoms or liters to molecules. The most important thing to do is to first recognize what you have and what your answer's units should be. From there, you can decide on you conversion factors. Here are some of them:
Molar Volume (of all gases @ STP):
22.4 L / 1 mol
Molar Volume (of all gases @ SATP-> Standard Ambient Temperature & Pressure):
24.8 L / 1 mol
Molar Mass:
grams (g) / 1 mol
Avogadro's Number:
EXAMPLE:
12.5 grams of Hydrogen (H2) are placed in a balloon at STP (Standard Temperature and Pressure = 0ยบ C & 101.3 kPa). Determine it's volume.
1. First, use molar mass as your conversion factor and cancel accordingly.
-> 12.5
2.0
*The mass in grams is 2.0 because there are hydrogen is diatomic.
2. Next, use molar volume as your conversion factor and cancel accordingly.
-> 12.5
2.0
3. Alter your answer to have the appropriate number of significant digits.
-> There are 1.4 x 10² Liters in 12.5 grams of Hydrogen.
There will be other instances where they ask you for more conversions such as grams to atoms or liters to molecules. The most important thing to do is to first recognize what you have and what your answer's units should be. From there, you can decide on you conversion factors. Here are some of them:
Molar Volume (of all gases @ STP):
22.4 L / 1 mol
Molar Volume (of all gases @ SATP-> Standard Ambient Temperature & Pressure):
24.8 L / 1 mol
Molar Mass:
grams (g) / 1 mol
Avogadro's Number:
6.02 x 10²³ molecules or atoms or fundamental units / 1 mol
Here are some links to help you out as well:
http://www.youtube.com/watch?v=tS9l-OxucQU
http://www.youtube.com/watch?v=AsqEkF7hcII&feature=related
http://www.youtube.com/watch?v=8TkY36qB1f0
Here are some links to help you out as well:
http://www.youtube.com/watch?v=tS9l-OxucQU
http://www.youtube.com/watch?v=AsqEkF7hcII&feature=related
http://www.youtube.com/watch?v=8TkY36qB1f0
Monday, December 6, 2010
Moles to Molecules
Remember Avogardo's number?
6.02 x 10^23
Well in this lesson we learned about how to convert Moles into Molecules
We did examples like:
-How many atoms are there in 1.5 mol of Iron?
We start off like this
1.5mol x __________
Since we have to cancel out moles, to cross multiply out the mols, you have to put 1 mol (usually) on the bottom
1.5mol x __________
1 mol
And remember Avogardo's number? Well plug it in the top!
1.5mol x 6.02 x 10^23 molecules
1 mol
So since the moles cancel out, we multiply 1.5 mol and Avogardo's number and we get....
6.02 x 10^23
Well in this lesson we learned about how to convert Moles into Molecules
We did examples like:
-How many atoms are there in 1.5 mol of Iron?
We start off like this
1.5mol x __________
Since we have to cancel out moles, to cross multiply out the mols, you have to put 1 mol (usually) on the bottom
1.5mol x __________
1 mol
And remember Avogardo's number? Well plug it in the top!
1.5mol x 6.02 x 10^23 molecules
1 mol
So since the moles cancel out, we multiply 1.5 mol and Avogardo's number and we get....
1.5mol x 6.02 x 10^23 molecules = 9.0 x 10^23
1 mol
Well thats all for today guys!
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